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3x − Y 2z = 3 2x Y 3z = 5 X − 2y − Z = 1 | Shaalaa.com
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: Thế (1) vào (2) ta được: x 3(2x 5) = 1 ⇔ x 6x 15 = 1 ⇔ 7x = -14 ⇔ x = -2 Thay x = -2 vào (1) ta được y = 2.(-2) 5 = 1 Vậy hệ phương trình có nghiệm duy nhất (-2;1) Chuyên đề Toán lớp 9 Thế (1) vào (2) ta được: -3(2y 4) 6y = -12 ⇔ -6y -12 6y = -12 ⇔ 0y = 0 (luôn đúng) Vậy hệ phương trình có vô số nghiệm (x;y) thỏa mãn x = 2y 4 và y ∈ R. || id:vyntuyetvoilamemoi || #chenyiheng #陈奕恒 #trandichhang #xhhtiktok #ilovetiktok
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